When you boot using grub4dos, there are two timeouts: the one in the menu.lst, which in the sample is set to 30;
but before that menu, there is the other coundown of 5 seconds. I can't figure out where that timeout is set.
Posted 24 February 2013 - 03:13 AM
When you boot using grub4dos, there are two timeouts: the one in the menu.lst, which in the sample is set to 30;
but before that menu, there is the other coundown of 5 seconds. I can't figure out where that timeout is set.
Posted 24 February 2013 - 07:40 PM
This makes no sense:
using a hex editor, I searced both grldr and grub.exe for the string: "pxe detect" , and soon saw: "timeout 1";
Yet, when invoking grub4dos on bootup, the prelude to the regular menu.lst(the one on the root drive) there is clearly
a *five* second timeout. I am stumped.
Posted 24 February 2013 - 07:45 PM
Let me clarify:
In the root-drive menu.lst, I am using 'timeout 30';
before that menu, the embedded menu.lst shows timeout 1, but it is counting down from 5.
Posted 24 February 2013 - 08:26 PM
What you don't mention is how you installed grub4dos???
Try installing grub4dos using RMPrepUSB.
If you use grubinst then use t=0 in the command line
It is the timeout before grub will boot from the previous MBR rather than load grldr.
Posted 25 February 2013 - 12:26 AM
Here is how I install grub4dos:
place grub.exe,grldr,grldr.mbr,and bootlace.com, as well as menu.lst on c:\ drive, which is fat32.
Execute: bootlace 0x80,
then execute grub, which brings up the usual grub4dos menu. This only has to be done once.
Posted 25 February 2013 - 01:07 AM
Amazing; just reinstalled grub4dos using grubinst(gui);set (hd0),only checked don't search for floppy,set t=1; BINGO! tnx all.
Still don't see where it is hiding though, as per the above.
Posted 25 February 2013 - 09:19 AM
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